14p^2-19pq-3q^2=

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Solution for 14p^2-19pq-3q^2= equation:


Simplifying
14p2 + -19pq + -3q2 = 0

Reorder the terms:
-19pq + 14p2 + -3q2 = 0

Solving
-19pq + 14p2 + -3q2 = 0

Solving for variable 'p'.

Factor a trinomial.
(2p + -3q)(7p + q) = 0

Subproblem 1

Set the factor '(2p + -3q)' equal to zero and attempt to solve: Simplifying 2p + -3q = 0 Solving 2p + -3q = 0 Move all terms containing p to the left, all other terms to the right. Add '3q' to each side of the equation. 2p + -3q + 3q = 0 + 3q Combine like terms: -3q + 3q = 0 2p + 0 = 0 + 3q 2p = 0 + 3q Remove the zero: 2p = 3q Divide each side by '2'. p = 1.5q Simplifying p = 1.5q

Subproblem 2

Set the factor '(7p + q)' equal to zero and attempt to solve: Simplifying 7p + q = 0 Solving 7p + q = 0 Move all terms containing p to the left, all other terms to the right. Add '-1q' to each side of the equation. 7p + q + -1q = 0 + -1q Combine like terms: q + -1q = 0 7p + 0 = 0 + -1q 7p = 0 + -1q Remove the zero: 7p = -1q Divide each side by '7'. p = -0.1428571429q Simplifying p = -0.1428571429q

Solution

p = {1.5q, -0.1428571429q}

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